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One of the most massive star known is ETA Carinae B, with 125 solar mass and 240 solar radii at periastron. What is the escape velocity of photon from its surface.

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Answer:

The escape velocity of photon from its surface=445625.7m/s

Step-by-step explanation:

We are given that

Radius, R=240 solar radii=
1.67* 10^(11) m

1 solar radii=
6.957* 10^8 m

Mass, m=125 solar mass=
2.486* 10^(32)kg

1 solar mass=
1.989* 10^(30)kg

We have to find the escape velocity of photon from its surface.

We know that escape velocity


v={\sqrt{(2GM)/(R)}

Using the formula


v=\sqrt{(2* 6.67* 10^(-11)* 2.486* 10^(32))/(1.67* 10^(11))}


v=445625.7m/s

Hence ,the escape velocity of photon from its surface=445625.7m/s

User Jason Roselander
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