Question

If the initial concentration of N2O5 was 0.500 M and the concentration of N2O5 was 0.450 M after 0.100 s, what is the average rate of NO2 formation during the first 100 milliseconds

Answer 1

The appropriate solution is "1 M/s".

Step-by-step explanation:

The equation is:

`2N_2O_5 \rightarrow4NO_2+O_2`

or,

`(1)/(2)(-(\Delta(N_2O_5))/(dt) ) =(1)/(4)(\Delta (NO_2))/(dt)`

then,

The rate of
`NO_2` formation:

=
`(\Delta NO_2)/(dt)`

=
`(4)/(2) (-(\Delta(N_2O_5))/(dt))`

=
`2(-(\Delta (N_2O_5))/(dt) )`

=
`2(-((0.45-0.5))/(0.1) )`

=
`1 \ M/s`