Question

Calculate the molarity of a potassium hydroxide solution if 25.0 ml of this solution was completely neutralized by 23.3 ml of 0.506 M sulfuric acid.

Answer 1

Answer: 0.943 M of potassium hydroxide solution is required.

Step-by-step explanation:

A neutralization reaction is defined as the reaction in which an acid reacts with a base to form a salt and water molecule.

To calculate the molarity of potassium hydroxide, the equation used is:

`n_1M_1V_1=n_2M_2V_2` ........(1)

where,

`n_1, M_1\text{ and }V_1` are the n-factor, molarity and volume of acid that is
`H_2SO_4`

`n_2, M_2\text{ and }V_2` are the n-factor, molarity and volume of the base that is KOH

We are given:

`n_1=2\\M_1=0.506M\\V_1=23.3mL\\n_2=1\\M_2=?M\\V_2=25.0mL`

Putting values in equation 1, we get:

`2* 0.506* 23.3=1* M_2* 25.0\\\\M_2=(2* 0.506* 23.3)/(1* 25.0)\\\\M_2=0.943M`

Hence, 0.943 M of potassium hydroxide solution is required.