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The measure of an angle ABC is 50°,AD bisects angle BAC, and DC bisects angle BCA. The measure of angle ADC is what?​

User Snibbets
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1 Answer

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Answer:

115°

Explanation:

Let A, B, C represent the vertex angle measures of ΔABC. Then the sum of angles in ΔADC is ...

A/2 +∠ADC + C/2 = 180°

Multiplying by 2 gives ...

A + C + 2×∠ADC = 360°

From the given information, we know ...

A + C + 50° = 180° . . . . . sum of angles in ΔABC

This lets us write an expression for (A +C):

A + C = 130° . . . . . . . . subtract 50° from the previous equation

Substituting for A+C, we get ...

130° + 2×∠ADC = 360°

2×∠ADC = 230° . . . . . . . . . subtract 130°

∠ADC = 115° . . . . . . . . . . . divide by 2

User Gluecksmelodie
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