Answer:
The volume of 55 grams of BF₃ is 18.1664 L.
Step-by-step explanation:
If the molar mass of compound BF₃ is 67.81
, then the number of moles 55 grams of compound contains is calculated as:
![55 grams* (1 mole)/(67.81 grams) = 0.811 moles](https://img.qammunity.org/2022/formulas/chemistry/high-school/548aajre9dd06z8109nt9u6ne1n5gyzdc1.png)
The STP conditions refer to the standard temperature and pressure. Pressure values at 1 atmosphere and temperature at 0 ° C are used and are reference values for gases. And in these conditions 1 mole of any gas occupies an approximate volume of 22.4 liters.
Then it is possible to apply the following rule of three: if by definition of STP 1 mole of a compound occupies 22.4 L, 0.811 moles of the compound occupies how much volume?
![volume=(0.811 moles* 22.4 L)/(1 mole)](https://img.qammunity.org/2022/formulas/chemistry/high-school/3i56o9701c8sg0q0a0uu5czwedgja2xbhd.png)
volume= 18.1664 L
The volume of 55 grams of BF₃ is 18.1664 L.