Question

What is the change in temperature, if a 70.0 gram sample of nickel absorbs 1756 J of energy? Nickel has a specific heat of 0.440 J/g °C.

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Answer 1

`\Delta T=57.01^(\circ) C`

Step-by-step explanation:

Given that,

The mass of nickel, m = 70 g

Energy absorbed, Q = 1756 J

The specific heat of Nickel, c = 0.440 J/g °C

We know that,

The heat absorbed is given by :

`Q=mc\Delta T\\\\\Delta T=(Q)/(mc)\\\\\Delta T=(1756)/(70* 0.44)\\\\=57.01^(\circ) C`

So, the change in temperature is equal to
`57.01^(\circ) C`.