Question

Please help with this math problem

Answer 1

• y=2x²-5x+6
• y=3x+3

Equate

• 2x²-5x+6=3x+3=0
• 2x²-8x+3=0

Solve for x

• x=8±√64-4(2)(3)/4
• x=8±√64-24/4
• x=8±√40/4
• x=8±2√10/4
• x=2±1/2√10

Answer 2

`x=2+½*√(10)`

or

`x=2-½*√(10)`

Answer:

Solution given:

y=2x²-5x+6.....[1]

y=3x+3.........….[2]

solving equation 1&2

2x²-5x+6=3x+3

2x²-5x-3x+6-3=0

2x²-8x+3=0

comparing above equation with ax²+bx+c=0 we get

a=2

b=-8

c=3

by using quadratic equation

`x=(+8±√((-8)²-4*2*3))/(2*2)`

`x=(+8±2√(10))/(4)`

taking positive

`x=(+8+2√(10))/(4)`

`x=2+½*√(10)`

taking negative

`x=2-½*√(10)`