Question

What is the value of √(18-6)^2+(17-1)^2

Answer 1

Problem:

What is the value of:

`\quad \quad \quad \quad\tt{ \sqrt{(18 - {6)}^(2)+ (17 - {1)}^(2)} }`

Let's try!

`\quad \quad \quad \quad\tt{ \sqrt{(18 - {6)}^(2)+ (17 - {1)}^(2)} }`

`\quad \quad \quad \quad\tt{ \sqrt{{(12)}^(2)+ {(16)}^(2)} }`

`\quad \quad \quad \quad\tt{ √(144+ 256) }`

`\quad \quad \quad \quad\tt{ √(400) }`

`\quad \quad \quad \quad\tt{ = 20}`

Hence, The answer is:

`\quad \quad \quad \quad \huge\boxed{ \tt{ \color{green}20}}`

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Answer 2

20

Explanation:

sqrt((18-6)^2+(17-1)^2)

Inside parentheses first

sqrt((12)^2+(16)^2)

Then square inside the parentheses

sqrt(144+256)

Sqrt(400)

Taking the square root

20