Question

If f(x)= 2x^5-3x^3+2x^2+1, then f(1)=?
A. -1
B. 0
C. 1
D. 2
E. 4

Answer 1

Problem:

`\tt{if \: \: f(x) = 2 {x}^(5) - 3{x}^(3) + 2 {x}^(2) + 1 \: \: then \: \: f(1) = ?}`

Let's try!

`\quad \quad \quad \quad \tt{f(x) = 2 {x}^(5) - 3 {x}^(3) + 2 {x}^(2) + 1}`

`\quad \quad \quad \quad \tt{f(x) = 2 {(1)}^(5) - 3 {(1)}^(3) + 2 {(1)}^(2) + 1}`

`\quad \quad \quad \quad \tt{f(x) = 2 (1) - 3 (1) + 2 (1) + 1}`

`\quad \quad \quad \quad \tt{f(x) = 2 - 3 + 2 + 1}`

`\quad \quad \quad \quad \tt{f(x) = 2 - 3 +3}`

`\quad \quad \quad \quad \tt{f(x) = 2 \: \: \cancel{ \color{red}- 3 +3}}`

`\quad \quad \quad \quad \tt{f(x) = 2 }`

Hence, The answer is:

`\quad \quad \quad \quad \huge\boxed{\tt{ \color{green}f(x) = 2 }}`

________

#LetsStudy

Answer 2

2

Explanation:

f(x)= 2x^5-3x^3+2x^2+1

Let x=1

f(1)= 2(1)^5-3(1)^3+2(1)^2+1

= 2*1 -3*1+2(1) +1

= 2-3+2+1

2