Answer:
8,9,10
Explanation:
Let x be the first integer
x+1 is the next consecutive integer
x+2 is the third consecutive integer
The sum is 27
x + (x+1) + (x+2) = 27
Combine like terms
3x+3 = 27
Subtract 3 from each side
3x+3-3 =27-3
3x =24
Divide by 3
3x/3 = 24/3
x=8
The integers are
x=8
x+1 =9
X+2 =10