Question

3kg ball traveling at 10 m/s east collides with 5 kg ball traveling at 2m/s east after the collision the balls stick together what is the final velocity of the 3kg ball ?

Answer 1

Step-by-step explanation:

The formula for this is designed around the fact that momentum must be conserved:

`[(m_(ball1)*v_(ball1))+(m_(ball2)*v_(ball2))]_b=[(m_(ball1)+m_(ball2))v_(both)]_a`

This is because they sitck together after they collide. Filling in:

[(3*10)+(5*2)] = [3 + 5]v and

30 + 10 = 8v so

40 = 8v and

v = 5

They are both moving east at a velocity of 5 m/s since they stuck together.