Question

A) If we have a 4.5 L container of CH 10 gas at a temperature of 178 K and a pressure of 0.50 atm, then how many moles of CaHio do

we have?
b) How many grams of C4H1o do we have?

Answer 1

a) 0.15 mol.

b) 8.95 g.

Step-by-step explanation:

Hello there!

In this case, according to the given information, it is possible for us to infer this problem is solved by using the ideal gas equation:

`PV=nRT`

And proceed as follows:

a) Here, we solve for the moles, n, as follows:

`n=(PV)/(RT) \\\\n=(0.50atm*4.5L)/(0.08206(atm*L)/(mol*K)*178K) \\\\n=0.15mol`

b) for the calculation of the mass, we recall the molar mass of butane, 58.12 g/mol, to obtain:

`0.15mol*(58.12g)/(1mol) =8.95g`

Regards!