Question

Consider the reaction between solid C and O2 gas which makes CO2;

C+02 -> CO2
If we have a 14 L container of O2 gas at a pressure of 3.0 atm and a temperature of 298 K and we add 36 g of solid C to the
container, then how many grams of CO2 will be produced by this reaction?

Answer 1

`m_(CO_2)=75.6gCO_2`

Step-by-step explanation:

Hello there!

In this case, according to the given information, it turns out mandatory for us to calculate the reacting moles of both C and O2 because we are given grams and pressure, temperature and volume, respectively:

`n_C=36gC*(1molC)/(12gC)=3.0molC \\\\n_(O_2)=(3.0atm*14L)/(0.08206(atm*L)/(mol*K)*298K)=1.72molO_2`

Thus, since C and O2 react in a 1:1 mole ratio, we infer C is in excess, and the grams of CO2 can be calculated with the moles of O2:

`m_(CO_2)=1.72molO_2*(1molCO_2)/(1molO_2)*(44.01gCO_2)/(1molCO_2) \\\\ m_(CO_2)=75.6gCO_2`

Best regards!