Answer:
![1.74molNO_2](https://img.qammunity.org/2022/formulas/chemistry/college/au33uyfntrekifm9zppson2pdhcskgcseu.png)
Step-by-step explanation:
Hello there!
In this case, according to the given information, it turns out possible for us to perform mole-mass relationships by using the molar mass of the involved substance, in this case NO2, which is 46.0 g/mol; then we just set up a conversion factor like the one shown below:
![80g*(1mol)/(46g)\\\\1.74molNO_2](https://img.qammunity.org/2022/formulas/chemistry/college/p8b2adztgdee00xwwc6fm4bly7uizdhj24.png)
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