9x {}^(2) y {}^(3) z {}^(5) / 6x {}^(3) yz {}^(2) ​

Question

`9x {}^(2) y {}^(3) z {}^(5) / 6x {}^(3) yz {}^(2)`
​

Answer 1

3y²z³ / 2x

Explanation:

we can take one term at a time:

9/6 can be simplified to 3/2

x²÷x³ = x^-1 which equals
`(1)/(x)`

y³÷y = y²

z⁵÷z² = z³

put it all together:

3·
`(1)/(x)`·y²·z³ / 2 or

3y²z³ / 2x