Question

1. How many molecules of S2 gas are in 756.2 L?

a. 2.032 x 1025 molecules S,

b. 3.022 x 1023 molecules S,

c. 4.302 x 10 molecules S

d. 8.203 x 10' molecules S2

Answer 1

Answer: There are
`2.032 * 10^(25)` molecules
`S_(2)` gas are in 756.2 L.

Step-by-step explanation:

It is known that 1 mole of any gas equals 22.4 L at STP. Hence, number of moles present in 756.2 L are calculated as follows.

`Mole = (Volume)/(22.4 L)\\= (756.2 L)/(22.4 L)\\= 33.76 mol`

According to mole concept, 1 mole of every substance contains
`6.022 * 10^(23)` molecules.

Therefore, molecules of S present in 33.76 moles are calculated as follows.

`1 mol = 6.022 * 10^(23)\\33.76 mol = 33.76 * 6.022 * 10^(23)\\= 2.032 * 10^(25)`

Thus, we can conclude that there are
`2.032 * 10^(25)` molecules
`S_(2)` gas are in 756.2 L.