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Which equation(s) have -4 and 4 as solutions? A. x2 = 8 B. x2 + 16 = 0 C. 2x2 = 32 D. -3x2 = -48 E. 6x2 + 56 = -40 F 27 - 5x2 = -53
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Which equation(s) have -4 and 4 as solutions?

A. x2 = 8
B. x2 + 16 = 0
C. 2x2 = 32
D. -3x2 = -48
E. 6x2 + 56 = -40
F 27 - 5x2 = -53

User Itay Merchav
by
3.4k points

1 Answer

3 votes
C because...
2x^2 = 32 becomes...
2x^2 - 32 = 0 (FACTOR OUT THE 2!)
2(x^2 - 16) = 0 —> now we have a difference of squares
2 (x + 4) (x - 4) = 0
Our two solutions are 4 and -4.
User Dervall
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3.6k points
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