Question

The length of a rectangle is 2 ft shorter than 5 times its width, x. The area of the rectangle is less than 100 f12.

Which inequality can be used to determine the maximum width (ft) of the rectangle?

A. 5x2 – 2x < 100

OB. 5x2 - 2x > 100

O C. 5x2 + 2x > 100

D. 5x2 + 2x < 100




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Answer 1

A

Explanation:

Area of rectangle = length x width

length = 5x - 2

width = x

area = (5x - 2) × x

100 = 5x² - 2x

the width would be less than the area of the rectangle, thus the inequality sign to be used is <

5x² - 2x < 100