Question

How do you solve f(x) = x2 + x - 20?​

Answer 1

`\huge \bf༆ Answer ༄`

Let's solve ~

`{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \: {x}^(2) + x - 20`

`{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \: {x}^(2) + 5x - 4x - 20`

`{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:x(x + 5) - 4(x + 5)`

`{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:(x + 5)(x - 4)`

It's factorized now ~ And if you want to find the zeros then equate the expression with 0.

And you will get ;

`{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:x = - 5 \: \: and \: \: 4`