Question

In ΔPQR, r = 9 inches, p = 6.6 inches and ∠Q=6°. Find the area of ΔPQR, to the nearest 10th of a square inch

Answer 1

3.104 which is equal to 3.1 it your answer.

Explanation:

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Answer 2

2.8 square inches

Explanation:

Area of the triangle PQR = 1/2 rp sin <Q

Given

r = 9in

p = 6.6in

<Q =6°

Substitute into the formula;

Area of the triangle PQR = 1/2 * 9 * 6 sin6°

Area of the triangle PQR = 9 * 3 sin6°

Area of the triangle PQR = 27 sin6°

Area of the triangle PQR = 27(0.1045)

Area of the triangle PQR = 2.82

Hence the area to the nearest 10th of a square inch is 2.8 square inches