Question

In AHIJ, the measure of ZJ=90°, the measure of ZH=57°, and IJ = 22 feet. Find the

length of HI to the nearest tenth of a foot.
X
22
57°
H

Answer 1

26.2

Explanation:

From the given diagram;

Opposite side IJ = 22

Hypotenuse HI = x

Angle of elevation = 57degrees

Using the SOH CAH TOA;

sin theta = opposite/hypotenuse

sin theta = IJ/HI

sin57 = 22/x

x = 22/sin57

x = 22/0.8387

x = 26.2

Hence the legnth of HI is 26.2