Answer:
The required specific enthalpy for oxygen = 8277.34 J/mol
Step-by-step explanation:
Given that :
Pressure = 2.4 atm
Temperature = 310 K
specific internal energy U = 5700 J/mol
To find the specific enthalpy using the formula:
H = U + PV
where;
H is known as the specific enthalpy
Recall that from ideal gas equation
PV = nRT
For specific enthalpy, it is constant that n = 1
Thus;
PV = RT
replacing that into the equation (H = U + PV), we have:
here;
R = 8.314 J/mol K (constant)
H = U + RT
H = 5700 J/mol +( 8.314 J/mol K × 310 K)
H = 5700 J/mol + ( 2577.34 J/mol)
H = 8277.34 J/mol