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The PH of a solution with a [H+] of 1x10^9 is ?
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The PH of a solution with a [H+] of 1x10^9 is ?

User Ayano
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1 Answer

3 votes

Answer:

9

Step-by-step explanation:

pH = -log[H+] = -log(1x10^9) = 9

User Bharat Bhushan
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