Question

Let h(x) = x*2 + kw - 8. If h(-1) = -5, what is the value of h(4)?
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Answer 1

h(4) = 0

Explanation:

Hoping its ' kx '

`h(x) = x^2 + kx -8 \\\\h(-1) = (-1)^2 + k(-1) - 8\\\\-5 = 1 - k -8\\\\-5 = -k -7\\\\-5 + 7 = -k\\\\2 = -k\\-2 = k`

Now we have k = -2. We will find h(4).

`h(4) = (4)^2 + (-2)(4) - 8 = 16 -8 - 8 = 0`

Answer 2

h(4) = 0

Explanation:

GIVEN :-

• A quadratic function h(x) = x² + kx - 8
• h(-1) = -5

TO FIND :-

• Value of h(4)

SOLUTION :-

To find the value of h(4) , you need to find 'k' first by using the given facts.

`h(-1) = (-1)^2 + k(-1) - 8 = -5`

`=> 1 - k - 8 = -5`

`=> -k - 7 = -5`

• Add both the sides by 7.

`=> -k - 7 + 7 = -5 + 7`

`=> -k = 2`

• Multiply both the sides by -1.

`=> -k(-1) = 2(-1)`

`=> k = -2`

Putting the value of k,

`h(4) = (4)^2 + (-2)(4) - 8`

`= 16 - 8 - 8`

`= 16 - 16`

`= 0`