Answer:
40,000 s
Step-by-step explanation:
Find the acceleration of the train given the mass and the force applied.
Convert 2 kN to N --> 2000 N.
Substitute the train's mass and applied force into Newton's 2nd Law:
- F = ma
- 2000 = 8,000,000 * a
- a = 0.00025 m/s²
SInce the train is slowing down, the acceleration should be negative.
Using the acceleration, initial velocity, final velocity, we can solve for time using this kinematic equation:
- v = v₀ + at
- 0 = 10 + (-.00025)t
- -10 = -.00025t
- t = 40000 s
It will take 40,000 seconds to bring the train to a stop if a 2 kN frictional force is applied.