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10 votes
10 votes
Find the value of K when K = 5n^2 + w. when n = 4 and w = -6.

User Patrick Hurst
by
2.5k points

2 Answers

7 votes
7 votes

Answer:

  • Value of k is 74

Explanation:

Here we have been provided with the values of n and w that is 4 and -6 respectively.

Equation that we have,

  • k = 5n² + w

Substituting the values of n and w in the equation,


\implies \: \sf{k \: = \: 5(4) {}^(2) \: + \: ( - 6)}


\implies \: \sf{k \: = \: 5(4 * 4) \: + \: ( - 6)}


\implies \: \sf{k \: = \: 5 \: (16) \: + \: ( - 6)}

Multiplying 16 by 5,


\implies \: \sf{k \: = \: 5 \: * 16 \: + \: ( - 6)}


\implies \: \sf{k \: = \: 80 \: + \: ( - 6)}


\implies \: \sf{k \: = \: 80 \: - \:6)}

Subtracting 6 from 80,


\implies \: \red{\bf{k \: = \: 74}}

Therefore, value of k is 74..!!

User Gcw
by
2.9k points
21 votes
21 votes

Answer:


\bold{K = 5n {}^(2) + w}

Given ,

value of n = 4

value of w = - 6

Then ,


\bold{K = 5(4) {}^(2) + ( - 6)} \\\bold{ K = 5(16) - 6} \\\bold{ K = 80 - 6} \\ \fbox\pink{K = 74}

hope helpful~

User GDY
by
3.1k points