Question

A house is on a hill 10 meters above the base of a 50 meter tall water tower. Calculate the gauge pressure at a tap on the ground floor of the house.

Density of water (rho) = 1000 kg/m^3

Acceleration of gravity (g) = 9.8 m/sec^2

Pressure of a fluid column ΔP=ρgΔh

SI units for pressure Pascal = 1 N/m^2 = 1 kg /ms^2


A) 98,000 N/M^2

B) 490,000 N/m^2

C) 588,000 N.m^2

D) 392,000 N/m^2

Answer 1

Step-by-step explanation:

Pressure of a fluid column ΔP=ρgΔh

delta h = 50-10 = 40

P = 1000x9.8x40

= 392000

ans is D

Answer 2

Step-by-step explanation:

Given: Pressure of a fluid column ΔP=ρgΔh

Density of water (ρ) = 1000 kg/m^3

Acceleration of gravity (g) = 9.8 m/sec^2

Δh = difference in height / elevation of water tower and tap

= 50 - 10

= 40

Substitute back into equation:

Pressure = 1000*9.8*40

= 392000 N/m^2

The answer is D.