∆x = (4--4)=8
∆y = (7--3)= 10
Explanation:
distance is given by;
d² = (∆y)²+ (∆x)²
d = √((∆y)²+ (∆x)²)
d = √((4+4)² + (7+3)²)
d = √((8²) + (10²))
d = √(64+100)
d = √164
d =12.806 units
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