Question

Calculate the force exerted on a thresher shark's eye by the hydrostatic pressure in ocean water at a depth of 380 m. (Assume the water's mass density at this depth is 1000 kg/m3k.)

Answer 1

Step-by-step explanation:

Hydrostatic pressure due to a water column of height h can be given by the following expression.

P = hρg

where ρ is density of water and g is acceleration due to gravity .

Substituting the values.

P = 380 x 1000 x 9.8

= 3.72 x 10⁶ Pa.

Answer 2

`F=(3.72* 10^6\ Pa)/(A)\ N`

Step-by-step explanation:

Given that,

The density of water, d = 1000 kg/m³

Depth, h = 380 m

We need to find the force exerted on a thresher shark's eye by the hydrostatic pressure in ocean water. The force exerted by the hydrostatic pressure is given by :

`P=\rho gh`

Put all the values,

`P=1000* 9.8* 380\\\\P=3.72* 10^6\ Pa`

Force exerted,

F = P/A

So,

`F=(3.72* 10^6\ Pa)/(A)\ N`

Where

A is the area of crosss section

Hence, this is the required solution.