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Solve the trigonometric equation for all values 0 ≤ x < 2π.

2sin^2 x-1 = 0






User Remy J
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1 Answer

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not really sure but hope this helps
Solve the trigonometric equation for all values 0 ≤ x < 2π. 2sin^2 x-1 = 0 ​ ​-example-1
User Sebastien Daniel
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