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A hot metal is placed in 100.0 g sample of water and it causes the temperature of the water to increase from 25 C to 27 C. How many joules of energy did the water absorb from the metal?

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Answer:
836.8\ J

Step-by-step explanation:

Given

Mass of water in the sample is
m=100\ g

Temperature changes from
25^(\circ)C to
27^(\circ)C

Change in temperature is
\Delta T=27-25=2^(\circ)C\ \text{or}\ 2\ K

We know, specific heat of water is
c=4.184\ J/g-K

Heat absorbed is given by


\Rightarrow Q=mc\Delta T\\\Rightarrow Q=100* 4.184* 2\\\Rightarrow Q=836.8\ J

Thus, water absorbs
836.8\ J of heat from hot plate.

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