Question

PLEASE HELP

what is the perimeter of a quadrilateral with vertices at (1,5), (6,5), (1,11), and (6,11)? enter the answer in the Ⴆσx

Answer 1

perimeter = 25.62 units

Explanation:

Let the quadrilateral be ABCD

A = (1, 5), B = (6, 5), C= (1, 11) , D = (6, 11)

To find the perimeter we need to add the lengths of sides AB , BC, CD, and AD.

Lets find the length of all sides using distance formula;

`distance = √((x_1-x_2)^2+(y_1-y_2)^2)`

`AB = √((1-6)^2+(5-5)^2) = √(25) = 5units\\\\BC= √((6-1)^2+(5-11)^2) = √(25+36) =√(61) units\\\\CD=√((1-6)^2 + (11-11)^2) = √(25) = 5units\\\\AD = √((1-6)^2+(5-11)^2) = √(25+36) = √(61)units`

Perimeter = AB + BC + CD + AD

`=10 + 2√(61) units` = 25.62 units