Question

A sample of a gas has a volume of 852 mL at 298 K. If the gas is cooled to 200K, what would the new volume be?

Answer 1

571.81 mL

Step-by-step explanation:

Assuming constant pressure, we can solve this problem by using Charles' law, which states that at constant pressure:

• V₁T₂=V₂T₁

Where in this case:

• V₁ = 852 mL

• T₂ = 200 K

• V₂ = ?

• T₁ = 298 K

We input the data:

• 852 mL * 200 K = V₂ * 298 K

And solve for V₂:

• V₂ = 571.81 mL

The new volume would be 571.81 mL.