Question

(please help!!!!!)
Factor the polynomial
b³-49b

Answer 1

`b(b+7)(b-7)`

Explanation:

Start by factoring a
`b` out:

`b(b^2-49b)`

For the term
`b^2-49b`, we're looking for two numbers that add up to 0 and multiply to be -49:

`7+(-7)=0,\\7\cdot -7=-49\\`

Two numbers:
`7\text{ and }-7`

Therefore, we have:

`\boxed{b(b+7)(b-7)\checkmark}`