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Find the volume of the right cone shown as a decimal rounded to the nearest tenth.

980.2 m^2
2205.4 m^2
3308.1 m^2
8821.6 m^2

Find the volume of the right cone shown as a decimal rounded to the nearest tenth-example-1
User Andrew Min
by
4.8k points

2 Answers

4 votes

Answer:


\huge\boxed{V=2204.3m^3}

Explanation:

The formula of a volume of a cone:


V=(1)/(3)\pi r^2H\\\\r-\text{radius}\\H-\text{height}

We have:


2r=18m\to r=(18m)/(2)=9m\\\\H=26m

substitute:


V=(1)/(3)\pi(9^2)(26)=(1)/(3)(81)(26)\pi=(27)(26)\pi=702\pi(m^3)

use π ≈ 3.14


V\approx(702)(3.14)=2204.28(m^3)\approx2204.3

User Intl
by
4.2k points
2 votes

Answer:

B

Explanation:

Radius = diameter / 2 = 18/2 = 9 m

Volume = (radius^2 x pi x height)/3 = (9^2 x pi x 26)/3 = 2205.4 m^3

User George Dimitriadis
by
4.4k points