Question

Point P is at (3,-3) it undergoes the transformation (x - 2, y + 3). Where is P' at?​

Answer 1

The coordinates of P' are
`P'(x,y) = (1, 0)`.

Explanation:

The coordinates of the point P' is determined by the following expression:

`P'(x, y) = P(x,y) + T(x,y)` (1)

Where:

`P(x,y)` - Original point.

`P'(x,y)` - Translated point.

`T(x,y)` - Translation vector.

If we know that
`P(x,y) = (3, -3)` and
`T(x,y) = (-2, 3)`, then the coordinates of point P':

`P'(x,y) = (3, -3) + (-2, 3)`

`P'(x,y) = (1, 0)`

The coordinates of P' are
`P'(x,y) = (1, 0)`.