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Identify the equation of the circle that has its center at (-8, 15) and passes through the origin A. (x – 8)2 + (y + 15)2 = 17 B. (x + 8)2 + (y – 15)2 = 289 C. (x - 8)2 + (y + 15)2 = 289 D. (x + 8)2 +
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Identify the equation of the circle that has its center at (-8, 15) and passes through the origin

A. (x – 8)2 + (y + 15)2 = 17
B. (x + 8)2 + (y – 15)2 = 289
C. (x - 8)2 + (y + 15)2 = 289
D. (x + 8)2 + (y - 15)2 = 17

User VRAwesome
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2 Answers

3 votes

Answer:

(x +8)^2 +(y -15)^2 = 289

Explanation:

User Trinchet
by
4.3k points
2 votes

Answer:

(x +8)^2 +(y -15)^2 = 289

Explanation:

User Null Set
by
4.3k points
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