Answer:
![3920\ J](https://img.qammunity.org/2022/formulas/physics/high-school/37zm45wrrm9wamev28kstwo3gnte2z4wb7.png)
Step-by-step explanation:
Given
mass of ball m=10 kg
It is placed at a height of 150 m
It is dropped from the height and allowed to free fall for 40 m
Velocity acquired by the ball during this fall is given by
![v^2-u^2=2as](https://img.qammunity.org/2022/formulas/physics/college/lss1j8602pgrepjhyty2tn7za1fzek6su9.png)
Insert u=0, a=g
![\Rightarrow v^2-0=2* 9.8* 40\\\Rightarrow v=√(784)\\\Rightarrow v=28\ m/s](https://img.qammunity.org/2022/formulas/physics/high-school/k6olt4njd2p71weq62w4tboefmuqzolvtd.png)
Kinetic energy at this instant
![K.E.=(1)/(2)* 10* 28^2\\\\\Rightarrow K.E.=3920\ J](https://img.qammunity.org/2022/formulas/physics/high-school/abvvt91wmt2lc9egtdl92rsumefz6vmc56.png)