Answer:
f(x-4) = x²-8x + 17
f(x-4)-f(-4) = x²-8x
Explanation:
Given the function:
f(x) = x^2+1
f(x-4) = (x-4)^2+1
f(x-4 ) = x² - 8x + 16 + 1
f(x-4) = x²-8x + 17
For f(x-4)-f(-4)
f(-4) = (-4)²+1
f(-4) = 16+1
f(-4) = 17
f(x-4)-f(-4) = x²-8x + 17 - 17
f(x-4)-f(-4) = x²-8x