Question

A Star fleet science officer drops a large rock from a height of 1.55 m onto the surface of an alien planet. The rock strikes the ground in 0.230 s. Determine the acceleration of gravity.

Answer 1

58.6 m/s²

Step-by-step explanation:

Applying,

s = ut+gt²/2............ equation 1

Where s = height of the rock, u = initial velocity, t = time, g = accelration due to gravity of the planet.

From the question,

Given: s = 1.55 m, t = 0.23 s, u = 0 m/s (dropped from an height)

Substitute these values into equation 1

1.55 = (0×0.23)+g(0.23²)/2

1.55 = 0.0529g/2

0.0529g = 3.1

g = 3.1/0.0529

g = 58.6 m/s²