Question

What is the pressure, in atm, of 24.5 L of ideal gas at 247.8 K if there are 1.8 moles present?

Answer 1

`\sf\longmapsto \: pressure = 1.5 \: atm`

Step-by-step explanation:

PV = NRT

We know,

Pressure=

`\sf (nrt)/(v)`

`\sf\longmapsto \: 1.8 \: moles * (0.082 \: atm \: (l)/(mol) \: k * 247.8k )\ \: ÷24.5 L`

`\sf\longmapsto \: pressure = 1.5 \: atm`

Answer 2

p = 1.5 atm

Step-by-step explanation:

pV = nRT

p = nRT/V = [1.8 mol×(0.082 atm L/mol K)×247.8 K]/24.5 L

p = 1.5 atm