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The following diagram shows part of the graph off with x-intercept (5,0) and y-intercept (0,8).

Find the y-intercept of the graph of f(x) + 3.

User Varunl
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Explanation:

By question , it's given that the X intercept is (5,0) and the y intercept is (0,8) . And we need to find the y-intercept of the graph of f(x) + 3 . For that , firstly let's find out the equation of the line.

  • We can use here two point form of the line .So that , the equation would be ,


\sf\implies y- y_1 = \bigg((y_2-y_1)/(x_2-x_1)\bigg) ( x - x_1) \\\\\sf\implies y - 0 = \bigg((0-8)/(5-0)\bigg)( x - 5 ) \\\\\sf\implies y = (-8)/(5)( x - 5 ) \\\\\sf\implies 5y = -8x +40 \\\\\sf\implies 8x + 5y - 40 = 0

Let us say that this is f(x) :-


\\\\\sf\implies f(x) = 8x + 5y - 40 \\\\\sf\implies \boxed{\sf\red{ f(x)+3 = 8x +5y -37 }}

Plot its graph :-

We can either convert it into intercept form but plotting a graph can also be done to find y intercept .


\implies \boxed{\pink{\sf y - intercept = 7.4}}

Refer to attachment for graph .

Hence the y Intercept is 7.4 .

The following diagram shows part of the graph off with x-intercept (5,0) and y-intercept-example-1
User Dan Allan
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