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Daniel drew a toy from a treasure chest containing 30 different toys. He selected a bouncy ball without replacement and then selected a key chain. What is the probability this could occur

1 Answer

2 votes

Answer:


Pr = (1)/(870)

Explanation:

Given


n =30

Required

Probability of selecting 2 toys of different types

From the question, we understand that all toys are different i.e. 1 of each type.

And the selection is without replacement;

So, after the first toy is selected; there are n - 1 toys left.

So, the probability is:


Pr = (1)/(n) * (1)/(n - 1)

Substitute
n =30


Pr = (1)/(30) * (1)/(30- 1)


Pr = (1)/(30) * (1)/(29)


Pr = (1)/(30*29)


Pr = (1)/(870)

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