Answer:
![Pr = (1)/(870)](https://img.qammunity.org/2022/formulas/mathematics/high-school/yf7j4ngq0ged7dvqx37zl8vgkamxcada8d.png)
Explanation:
Given
![n =30](https://img.qammunity.org/2022/formulas/mathematics/high-school/ujg7wydc5gec2pguo513amdshil749qgrr.png)
Required
Probability of selecting 2 toys of different types
From the question, we understand that all toys are different i.e. 1 of each type.
And the selection is without replacement;
So, after the first toy is selected; there are n - 1 toys left.
So, the probability is:
![Pr = (1)/(n) * (1)/(n - 1)](https://img.qammunity.org/2022/formulas/mathematics/high-school/84iq24dumhnoe7zi8n3ifaz5aau8ld0i2t.png)
Substitute
![n =30](https://img.qammunity.org/2022/formulas/mathematics/high-school/ujg7wydc5gec2pguo513amdshil749qgrr.png)
![Pr = (1)/(30) * (1)/(30- 1)](https://img.qammunity.org/2022/formulas/mathematics/high-school/ox8rjr3r3gfurbzm4sh58tl92eiueiv9hn.png)
![Pr = (1)/(30) * (1)/(29)](https://img.qammunity.org/2022/formulas/mathematics/high-school/q2p9bvqwo19f4akvh1rrsu4wrzc59ndju6.png)
![Pr = (1)/(30*29)](https://img.qammunity.org/2022/formulas/mathematics/high-school/xky5qtxzkceizzzzhualkyrp4ycf854mt2.png)
![Pr = (1)/(870)](https://img.qammunity.org/2022/formulas/mathematics/high-school/yf7j4ngq0ged7dvqx37zl8vgkamxcada8d.png)