Question

A 0.5-kg ball moving at 5 m/s strikes a wall and rebounds in the opposite direction with a speed of 2 m/s. If the impulse occurs for a time duration of 0.01 s, find the magnitude of the net force on the ball.

Answer 1

Answer: 350 N

Step-by-step explanation:

Given

Mass of ball is
`0.5\ kg`

Speed of ball after rebound is
`v=2\ m/s`

Time period for impulse
`t=0.01\ s`

Impulse imparted in equal to the change in the momentum of object

`\Rightarrow J=m(v-u)\quad [\text{u=speed of ball before collision}]\\\Rightarrow J=0.5* \left(2-(-5)\right)\\\Rightarrow J=0.5* 7\\\Rightarrow J=3.5\ N.s`

Impulse is the product of average force and duration of application

`\Rightarrow J=F_(avg)\cdot \Delta t\\\Rightarrow 3.5=F_(avg)* 0.01\\\\\Rightarrow F_(avg)=350\ N`