Question

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Answer 1

10.5

Explanation:

`KET\cong KIT...... (given)`

`\therefore KE \cong KI.... (csct)`

`\therefore m(KE) =m(KI)`

`\therefore 10x-34= 4x + 29`

`\therefore 10x-4x= 34 + 29`

`\therefore 6x= 63`

`\therefore x=(63)/(6)`

`\therefore x=10.5`