Question

In ΔNOP, the measure of ∠P=90°, PO = 48, NP = 55, and ON = 73. What is the value of the sine of ∠N to the nearest hundredth?

Answer 1

0.66

Explanation:

sin 90°/ 73 = sin L N /48

=> sin L N = 48×sin90° /73

= 48/73 = 0.66