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In ΔNOP, the measure of ∠P=90°, PO = 48, NP = 55, and ON = 73. What is the value of the sine of ∠N to the nearest hundredth?

User Rishi Kant
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1 Answer

2 votes

Answer:

0.66

Explanation:

sin 90°/ 73 = sin L N /48

=> sin L N = 48×sin90° /73

= 48/73 = 0.66

User Ywiyogo
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