Question

There were 24 students running in a race. How many different arrangements of first,

second, and third place are possible?

Answer 1

There are 12,144 different arrangements of first, second, and third place in the race.

Step-by-step explanation:

To find the number of different arrangements of first, second, and third place in a race with 24 students, we can use the concept of permutations. Since the order matters, we use the formula for permutations. The number of permutations of 24 students taken 3 at a time is given by:

P(24, 3) = 24! / (24 - 3)! = 24! / 21! = 24 × 23 × 22 = 12,144

Therefore, there are 12,144 different arrangements of first, second, and third place in the race.

Answer 2

24*23*22=12144
24P3
Use Permutation Formula