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Solve the equation for all real solutions.

Solve the equation for all real solutions.-example-1

1 Answer

5 votes

Answer:


d=(5)/(2),\\\\d=(2)/(5)

Explanation:

You can use the quadratic formula for any quadratic. The quadratic formula is given by
(-b\pm√(b^2-4ac))/(2a), and yields both real and non-real solutions.

In the given equation
10d^2-29d+10=0, we have:


a=10,\\b=-29,\\c=10

Substituting given values into the quadratic formula, we have:


x=(29\pm√((-29)^2-4(10)(10)))/(2(10)),\\\\x=(29\pm√(441))/(20),\\\\x=(29\pm 21)/(20),\\\\\begin{cases}x=(29+21)/(20),x=(50)/(20)=\boxed{(5)/(2)}\\x=(29-21)/(20), x=(8)/(20)=\boxed{(2)/(5)}\end{cases}

The attempt in the problem is correct. Sometimes with auto-grading, the solutions need to be in a specific order to be marked correct. I'd suggest submitting the solutions in a different order to check if that's the issue.

User Daerik
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